Euclid, Elements of Geometry, Book I, Proposition 15
(Edited by Sir Thomas L. Heath, 1908)

Proposition 15
[Euclid, ed. Heath, 1908, on archive.org]

If two straight lines cut one another, they make the vertical angles equal to one another.

For let the straight lines AB, CD cut one another at the point E;
I say that the angle AEC is equal to the angle DEB,
and the angle CEB to the angle AED.

A B C D E

For, since the straight line AE stands on the straight line CD, making the angles CEA, AED,
the angles CEA, AED are equal to two right angles. [I. 13]

Again, since the straight line DE stands on the straight line AB, making the angles AED, DEB,
the angles AED, DEB are equal to two right angles [I. 13]

But the angles CEA, AED were also proved equal to two right angles;
therefore the angles CEA, AED are equal to the angles AED, DEB. [Post. 4 and C.N. 1]
Let the angle AED be subtracted from each;
therefore the remaining angle CEA is equal to the remaining angle BED. [C.N. 3]

Similarly it can be proved that the angles CEB, DEA are also equal.

Therefore, etc. Q.E.D.

[PORISM. From this it is manifest that, if two straight lines cut one another, they will make the angles at the point of section equal to four right angles.]


Book I: Euclid, Elements, Book I (ed. Sir Thomas L. Heath 1st Edition, 1908)

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